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-4.9x^2+25x+50=0
a = -4.9; b = 25; c = +50;
Δ = b2-4ac
Δ = 252-4·(-4.9)·50
Δ = 1605
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{1605}}{2*-4.9}=\frac{-25-\sqrt{1605}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{1605}}{2*-4.9}=\frac{-25+\sqrt{1605}}{-9.8} $
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